picked one up to try it and I am honestly really not a fan
It tastes very sugar-y
And I donât mean âsweetâ so much as I mean âspecifically tastes like sugarâ in a way I donât really like all that much
I will very happily pay the extra dollar per tub to continue getting the Oikos Triple Zero on taste alone (not to mention that, to your cost point, the Oikos has 17g of protein per serving instead of 14g so itâs actually extremely comparable cost-to-protein-ratio-wise to the Dannon)
would recommend giving the oikos a shot at least once
You can remove the black square between R1C6 and R2C6. It did not restrict the placement of [5] whatsoever, and that boxâs column was my final steps, so the square did not provide me any purpose besides confirming that my solution is correct.
*backtracks*
I think⊠the black square between R6C3 and R7C3 is also unnecessary?
I already got [4] in R7C1 thanks to the clues in [R7, C1~3].
Afterwards I knew R6C1 had to be [8], and that [R6~7, C2] had to be [1,2]. That realization solved [R7, C2~3].
Since you already put a white diamond between R6C2 and R6C3, the latterâs solution is already fixed the moment I understood [R6~7, C2] were [1,2].
You donât need the black square betweenâŠ
R5C6 and R5C7.
R5C9 and R6C9.
Considering you already have the black squares in Box 7, you can quickly determine where [7] is in that Box. In tandem with the black squares in Box 8, you donât need the white diamond in B8 C5.
Am getting too lazy to explain + Pretty sure there are multiple paths to the correct solution.
first glance I need that to even be able to start solving. (it restricts the [5] in box 8) (also it makes extremely clear that the white squares are kropkis, since there are 7 cells connected with black squares in box 8)
No you donât. Itâs already covered by the white diamond in {5.5, 2} and the black square in {6.5, 2}.
Hm⊠For these ones, I didnât consider the restriction of the placement of [5]âŠ
The first one (i.e., {4.5, 6} ) is actually necessary in hindsight to avoid placing [5] at R5C7.
The second one (i.e., {5, 8.5} ) is still unnecessary though, since R7C9âs [5] covers for C9âs restriction.
Iâll be real here, I donât think I have ever said anything about the black square between R7C6 and R7C7.
So yes: I understand why you (correctly) think the puzzle becomes unsolvable.
But also: I never said anything about itâŠ