22852nd poster gets a cookie (cookie thread (Part 7)) (Part 10)

(Then why are you giving it to me…?)
Sigh… Give me a moment to start up my laptop.

I gave up after ~60 minutes. I had to spend around ~5 minutes to get the letter to work.

james franklin

Check row 3.
Where you can put a [5] ?

5 in R3C12
C in R3C11

I assume next step is counting low numbers in R3?

I solved the daily Clues by Sam (Oct 13th 2025) in 03:47
:green_square::green_square::green_square::green_square:
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:green_square::green_square::green_square::green_square:
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Yes, I think.

(It should force the 4-6 pair.)

Before you ask, why R3c1 can’t be [4]:

C1 Renban is forced to have a 4 on it (cause C=1), But CBR all are taken in box 4 via the kropki.

Clues by Sam - Oct 13th 2025
Less than 8 minutes
:green_square::green_square::green_square::green_square:
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Me no comprehendo.

spolier

In C1 the renban’s highest value can be 12, but because C=1 C, B, R can’t be 10, 11, 12.
So the max value on the renban is 11.
Since the renban has a length of 8, it has to have 8 different values. [Technicqlly the values, that all have to be on the renban are [4-8] but we only care about 4, 5, 6 right now, since 7 and 8 are still easily replacable at this point in box 7]
Kropki in box 4 needs all of 1, 2, 4, 8 R, B and C to be solveable, the values (4,5 and 6) on the renban can’t be replaced with RBC. Ergo all 3 of these numbers has to be on the renban line. (Which means, these numbers can’t be R3c1, so they have to be on the GW line.)
In row 3, C is already placed (and has 5 on one side.) Since C=11, technically 6 can be next to the C, but if you do that, there will be a contradiction.
Neither B or R can be higher than 3, so they have to neighbour a high number (on both sides, if necessary.) So the (low-high) parity of GW has to change every time. And if you follow this logic. R3C2 and R3C10 has to have the same parity. So if you place a [6] on R3C10, R3C2 has to be a high number. Which means, the [4] on the GW needs to have two high number as a neigbour, but only [9] is applicable (since neither B or R can be it’s neighbor.)

So R3C10 has to be a low number, and [6] has to have 2 low number as a neighbour, which literally can happen only on 1 space in row 3.

And this is only the start of the solve…

I managed to solve it in around 90 minutes, so this is quite a complex puzzle. (Also this doesn’t include the time, when I mislead myself thinking that B means the position inside the Box, and not the Box number, before I reread the rules again, when I confused myself.)

Fermi Question of the Day: “How many copies of Minecraft have been sold worldwide as of April 2025?”

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I solved the daily Clues by Sam (Oct 13th 2025) in 04:21
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:green_square::green_square::green_square::green_square:
:green_square::green_square::green_square::green_square:
:green_square::green_square::green_square::green_square:

Fermi Question of the Day: “How many copies of Minecraft have been sold worldwide as of April 2025?”

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1 Like

I solved the daily Clues by Sam (Oct 13th 2025) in 03:39
:green_square::green_square::green_square::green_square:
:yellow_square::green_square::green_square::green_square:
:green_square::green_square::green_square::green_square:
:green_square::green_square::green_square::green_square:
:green_square::green_square::green_square::green_square:

Miscounted :(

2 Likes

Oh, is today your birthday?
@Atlas has betrayed us.

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Happy birthday once again!
How’s it feel to be an adult?

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It’s great, I can feel all of the moral & legal responsibility entering my body

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:+1:

i blame benguined

4 Likes