It was the integral of cos^2(x) from 0 to 2pi
OH
ok I see what you mean
thatâs an evil integral trick tho thbthtbhtbthbth
I should really memorize the power reduction formulas tbhtbhtbhtbhtbht
and all the other trig identities
Bounds of integration problem:
Consider the region D defined by the following inequaltiies:
x>=0
y>=0
z>=0
z<=1-x^4
x^4+y^2+z^2<=1
Write hte iterated integral of the enclosed volume wit hthe order of integration being y,x,z, hten y,z,x, then z,y,x, then compute the integral for f(x,y,z)=(x^4+z)/sqrt(1-x^4-z^2) with the order of your choice
This is NOT, like, a difficult problem in THEORY. But I spent the first half with the order of integration swapped up in my mind, and I was very tired, and visualisation is hard
I wasnât expected to know the trick I just came u with it after
He just expected me to have it memorised
I only got the one for y,x,z before he Kicked me out of the exam
nyaaaaaaa every time I see a math problem like this in here I go âI should remember how to do thisâ and get nerd-baited into reviewing it
whenever i see a math problem i remember that math was the one subject i was terrible at
If you do a coordinate transform of x^4=a^2 itâs spherical which is nice I guess
you know now that im listing the subjects in my head i think i was exclusively good at a few things
Iâm trying to figure out how to do the first one thbthtbhtbt
I see y goes from 0 to 1
then x goes from 0 to 1 - y^2
then z goes from 0 to⌠min(1 - x^4, sqrt(1 - x ^ 4 - y^2))
is that last bound fine? am I supposed to see a way to remove the min?
APPARENTLY. They mean that y is the innermost integral and z is the outermost
z,y,x is the only one where you have to sum two integrals
âŚoh
THIS IS STUPID!!! THIS IS DUMB AND STUPID!!!
I guess that makes sense in terms of âwhat you integrate firstâ but also nyaaaaaaaaaaaaaaaaaaa
feels ~arbitrary either way
Yeah itâs arbitrary!!! I thought I was cheating by doing it the way it was apparently INTENDED. I spent like thrity minutes staring at this paper