But why r1c1 has to be mid numbers?
Can’t r2c1 simply be a 4, 5 or 6?
…can’t be 46 because of Block 2 and 4, but you’re right: I forgot about 5s. Technically yellow in Block 1 can be 5 if it is located exactly in R2C1. (Can’t be R1 'cuz of Block 2.)
Its not a new song silly of course ive watched it 
its great
…So which graphical part of the song did you like
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Im dunno. The first
Right…
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Left…
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*…Left
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nonono your left would be more to the right this way, smh
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chompsie popsie
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Since r2c4 can’t be 3 so r2c6 can’t be 4.
And r2c6 can’t be 7 so r2c4 can’t be 6.
This resolves the 46 pairs in box 5. (Both solution halves that pair the same way.)
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Liquid Kitty
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Following the same logic on the renban lines in box 4 and 6 makes a 37 pair in r5c1 and r5c9, which forces the 2 in box 4 in one cell, and the 8 in box 6 in an other. (Both of them solves the renban lines in their boxes.)
Solved it. It was painful.
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Well, I’m stuck at 70 minutes…
Where is [2] in Box 8?
It’s rather funny, because I was able to proceed when you mentioned “force 2 in box 4” when I was stuck.
Right, it was forced on the renban and solved the 46 in box 8 and 2. (I was looking only at single cells…)
Finished in 80:14 (thanks to your help)
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